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What is the approximate BAC for a 160-pound man who drank five 12-ounce beers in one hour?

  1. .081

  2. .101

  3. .121

  4. .141

The correct answer is: .101

To determine the blood alcohol concentration (BAC) for a 160-pound man who consumes five 12-ounce beers in one hour, it's essential to consider several factors including body weight, the total amount of alcohol consumed, and the time over which that alcohol is consumed. Each standard beer contains about 0.6 ounces of pure alcohol. Therefore, five 12-ounce beers would contain approximately 3 ounces of alcohol in total (0.6 ounces per beer multiplied by 5). When calculating BAC, the Widmark formula is often used, which is: \[ \text{BAC} = \left( \frac{\text{Alcohol consumed in ounces} \times 100}{\text{Body weight in ounces} \times r} \right) - 0.015 \times \text{Hours since first drink} \] In this case, a 160-pound man weighs roughly 72.57 kilograms, which is around 160 ounces. For men, the alcohol distribution ratio (r) is typically around 0.68. Plugging the numbers into the equation gives: 1. Total alcohol in ounces: 3 ounces. 2. Body weight in ounces: 160 ounces. 3. The duration is 1 hour.